Exercise 2.1 1. Which of the following expressions are polynomials in one variable and which are not? State reasons for your answer. (i) 4×2–3x+7 Solution: The equation 4×2–3x+7 can be written as 4×2–3×1+7×0 Since x is the only variable…

Exercise: 6.1 1. In Fig. 6.13, lines AB and CD intersect at O. If ∠AOC +∠BOE = 70° and ∠BOD = 40°, find ∠BOE and reflex ∠COE. Solution: From the diagram, we have (∠AOC +∠BOE +∠COE) and…

Exercise: 10.1 1. Fill in the blanks: (i) The centre of a circle lies in ____________ of the circle. (exterior/ interior) (ii) A point, whose distance from the centre of a circle is greater than its radius…

Exercise 11.1 1. Construct an angle of 90° at the initial point of a given ray and justify the construction. Construction Procedure: To construct an angle 90°, follow the given steps: 1. Draw a ray OA 2….

Exercise 1.1 1. Using appropriate properties find. (i) -2/3 × 3/5 + 5/2 – 3/5 × 1/6 Solution: – -2/3 × 3/5 + 5/2 – 3/5 × 1/6 = -2/3 × 3/5– 3/5 × 1/6+ 5/2 =…

Exercise 2.1 Solve the following equations. 1. x – 2 = 7 Solution: – x – 2 = 7 x=7+2 x=9 2. y + 3 = 10 Solution: – y + 3 = 10 y = 10…

Exercise 3.1 1. Given here are some figures. Classify each of them on the basis of the following. Simple curve (b) Simple closed curve (c) Polygon (d) Convex polygon (e) Concave polygon Solution: – a) Simple curve:…

Exercise 4.1 1. Construct the following quadrilaterals. (i) Quadrilateral ABCD AB = 4.5 cm BC = 5.5 cm CD = 4 cm AD = 6 cm AC = 7 cm Solution: – The rough sketch of the…

Exercise 5.1 1. For which of these would you use a histogram to show the data? (a) The number of letters for different areas in a postman’s bag. (b) The height of competitors in an athletics meet….

Exercise 6.1 1. What will be the unit digit of the squares of the following numbers? i. 81 ii. 272 iii. 799 iv. 3853 v. 1234 vi. 26387 vii. 52698 viii. 99880 ix. 12796 x. 55555 Solution:…

Exercise 7.1 1. Which of the following numbers are not perfect cubes? (i) 216 Solution: – By resolving 216 into prime factor, 216 = 2×2×2×3×3×3 By grouping the factors in triplets of equal factors, 216 = (2×2×2)×(3×3×3)…